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	<title>Comments on: Great Circle question</title>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6944</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6944</guid>
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  &lt;p&gt;Tom T. wrote: &lt;br /&gt; &gt; ... Isn&#039;t it required for a great circle route to be &lt;br /&gt; &lt;br /&gt;the intersection of the surface of the earth with a plane passing &lt;br /&gt; through the two points of interest (A and B) and the center of &lt;br /&gt; the earth? &#160; &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&gt; If you shoot a beam of light directly from A to B, even if it &lt;br /&gt; &lt;br /&gt;were to follow the curved surface of the earth, I don&#039;t believe &lt;br /&gt; this would always result in a great circle route. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;Think of it this way. Wherever you stand on the surface of the &lt;br /&gt; earth, there is an imaginary straight line between you and the &lt;br /&gt; centre of the earth. When you shoot a beam of light (or a radio &lt;br /&gt; wave) from where you are (point A) to point B, that also forms a &lt;br /&gt; straight line. Those two straight lines intersect at point A and &lt;br /&gt; by definition describe a plane which (a) passes through the &lt;br /&gt; centre of the earth and (b) contains the beam of light as it &lt;br /&gt; follows the earth&#039;s surface. Therefore, the beam of light *must* &lt;br /&gt; follow a great circle. &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>Tom T. wrote: <br /> &gt; &#8230; Isn&#8217;t it required for a great circle route to be </p>
<p>the intersection of the surface of the earth with a plane passing <br /> through the two points of interest (A and B) and the center of <br /> the earth? &nbsp;  </p>
<p>&gt; If you shoot a beam of light directly from A to B, even if it </p>
<p>were to follow the curved surface of the earth, I don&#8217;t believe <br /> this would always result in a great circle route.  </p>
<p>Think of it this way. Wherever you stand on the surface of the <br /> earth, there is an imaginary straight line between you and the <br /> centre of the earth. When you shoot a beam of light (or a radio <br /> wave) from where you are (point A) to point B, that also forms a <br /> straight line. Those two straight lines intersect at point A and <br /> by definition describe a plane which (a) passes through the <br /> centre of the earth and (b) contains the beam of light as it <br /> follows the earth&#8217;s surface. Therefore, the beam of light *must* <br /> follow a great circle. </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6942</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6942</guid>
		<description>
  &lt;p&gt;Robert Allardyce wrote: &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&gt; Sorry guys, a VOR radial isn&#039;t a GCc. It is a magnetic course. Need a &lt;br /&gt; &gt; magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), &lt;br /&gt; &gt; is a constant curve (i.e., constantly changing mag course), albeit, on &lt;br /&gt; &gt; short legs it would be hard to tell the difference. &lt;br /&gt; &lt;br /&gt;It&#039;s only aligned with magnetic north at the station (sometimes not even &lt;br /&gt; then). &#160;A radio wave doesn&#039;t know magnetic from nothing, it travesl in &lt;br /&gt; a straight line. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;A Great Circle course is not a curve except over the curvature of the &lt;br /&gt; earth. &#160;What is constantly changing is the heading because the relative &lt;br /&gt; direction of &quot;north&quot; changes as you fly most courses. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;-Ron &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>Robert Allardyce wrote:  </p>
<p>&gt; Sorry guys, a VOR radial isn&#8217;t a GCc. It is a magnetic course. Need a <br /> &gt; magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), <br /> &gt; is a constant curve (i.e., constantly changing mag course), albeit, on <br /> &gt; short legs it would be hard to tell the difference. </p>
<p>It&#8217;s only aligned with magnetic north at the station (sometimes not even <br /> then). &nbsp;A radio wave doesn&#8217;t know magnetic from nothing, it travesl in <br /> a straight line.  </p>
<p>A Great Circle course is not a curve except over the curvature of the <br /> earth. &nbsp;What is constantly changing is the heading because the relative <br /> direction of &quot;north&quot; changes as you fly most courses.  </p>
<p>-Ron </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6943</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6943</guid>
		<description>
  &lt;p&gt;&gt; VOR signals do not need to follow the curve of the earth. &#160;They are line &lt;br /&gt; &gt; of sight. &#160;But they still travel in straight lines, and a give VOR radial &lt;br /&gt; &gt; will be a plane that follows the area over the great circle. &lt;br /&gt; &lt;br /&gt;I hadn&#039;t thought of it that way, but yes, of course that&#039;s correct. &#160;If &lt;br /&gt; you follow a VOR radial along the lower altitude limit of reception, &lt;br /&gt; you&#039;ll keep climbing to stay within reception range, but your ground track &lt;br /&gt; will certainly be a great circle. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;-- &lt;br /&gt; Roy Smith &lt;r...@nyu.edu&gt; &lt;br /&gt; Hippocrates Project, Department of Microbiology, Coles 202 &lt;br /&gt; NYU School of Medicine, 550 First Avenue, New York, NY 10016 &lt;br /&gt; &quot;This never happened to Bart Simpson.&quot; &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>&gt; VOR signals do not need to follow the curve of the earth. &nbsp;They are line <br /> &gt; of sight. &nbsp;But they still travel in straight lines, and a give VOR radial <br /> &gt; will be a plane that follows the area over the great circle. </p>
<p>I hadn&#8217;t thought of it that way, but yes, of course that&#8217;s correct. &nbsp;If <br /> you follow a VOR radial along the lower altitude limit of reception, <br /> you&#8217;ll keep climbing to stay within reception range, but your ground track <br /> will certainly be a great circle.  </p>
<p>&#8211; <br /> Roy Smith &lt;r&#8230;@nyu.edu&gt; <br /> Hippocrates Project, Department of Microbiology, Coles 202 <br /> NYU School of Medicine, 550 First Avenue, New York, NY 10016 <br /> &quot;This never happened to Bart Simpson.&quot; </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6940</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:48 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6940</guid>
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  &lt;p&gt;ttur...@samson.hac.com writes: &lt;br /&gt; &gt; &#160;Maybe someone already responded to this, but if not I&#039;ll raise the &lt;br /&gt; &gt; &#160;question... Isn&#039;t it required for a great circle route to be the &lt;br /&gt; &gt; &#160;intersection of the surface of the earth with a plane passing &lt;br /&gt; &gt; &#160;through the two points of interest (A and B) and the center of the &lt;br /&gt; &gt; &#160;earth? &lt;br /&gt; &lt;br /&gt;Yup, that sounds good. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&gt; &#160;If you shoot a beam of light directly from A to B, even if it were &lt;br /&gt; &gt; &#160;to follow the curved surface of the earth, I don&#039;t believe this would &lt;br /&gt; &gt; &#160;always result in a great circle route. &lt;br /&gt; &lt;br /&gt;Yes it would. &#160;Although visible light won&#039;t follow the curvature of the &lt;br /&gt; Earth&#039;s surface, if you try some other sort of electromagnetic radiation of &lt;br /&gt; a slightly lower frequency (say, 1 MHz), it&#039;ll follow the surface just fine, &lt;br /&gt; and yes indeed, it will trace out a great circle. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;The problem is that great circles are hard for people to visualize (take a &lt;br /&gt; course in celestial navigation, and you&#039;ll be cured of that problem) because &lt;br /&gt; they&#039;re used to looking at globes with lat/long lines painted on them. &#160;Just &lt;br /&gt; remember, there is nothing magic about lat/long. &#160;It&#039;s just a somewhat &lt;br /&gt; arbitrary coordinate system that&#039;s in common use. &#160;If you wanted to, you &lt;br /&gt; could draw a lat/long-like coordinate system using any point on the Earth&#039;s &lt;br /&gt; surface as the north pole. &#160;That&#039;s essentially what you&#039;re doing when you &lt;br /&gt; draw great-circles from A to B; you&#039;re using A as your &quot;north pole&quot;, and &lt;br /&gt; putting B on a meridian. &lt;br /&gt; -- &lt;br /&gt; Roy Smith &lt;r...@nyu.edu&gt; &lt;br /&gt; Hippocrates Project, Department of Microbiology, Coles 202 &lt;br /&gt; NYU School of Medicine, 550 First Avenue, New York, NY 10016 &lt;br /&gt; &quot;This never happened to Bart Simpson.&quot; &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p><a href="mailto:ttur...@samson.hac.com">ttur&#8230;@samson.hac.com</a> writes: <br /> &gt; &nbsp;Maybe someone already responded to this, but if not I&#8217;ll raise the <br /> &gt; &nbsp;question&#8230; Isn&#8217;t it required for a great circle route to be the <br /> &gt; &nbsp;intersection of the surface of the earth with a plane passing <br /> &gt; &nbsp;through the two points of interest (A and B) and the center of the <br /> &gt; &nbsp;earth? </p>
<p>Yup, that sounds good.  </p>
<p>&gt; &nbsp;If you shoot a beam of light directly from A to B, even if it were <br /> &gt; &nbsp;to follow the curved surface of the earth, I don&#8217;t believe this would <br /> &gt; &nbsp;always result in a great circle route. </p>
<p>Yes it would. &nbsp;Although visible light won&#8217;t follow the curvature of the <br /> Earth&#8217;s surface, if you try some other sort of electromagnetic radiation of <br /> a slightly lower frequency (say, 1 MHz), it&#8217;ll follow the surface just fine, <br /> and yes indeed, it will trace out a great circle.  </p>
<p>The problem is that great circles are hard for people to visualize (take a <br /> course in celestial navigation, and you&#8217;ll be cured of that problem) because <br /> they&#8217;re used to looking at globes with lat/long lines painted on them. &nbsp;Just <br /> remember, there is nothing magic about lat/long. &nbsp;It&#8217;s just a somewhat <br /> arbitrary coordinate system that&#8217;s in common use. &nbsp;If you wanted to, you <br /> could draw a lat/long-like coordinate system using any point on the Earth&#8217;s <br /> surface as the north pole. &nbsp;That&#8217;s essentially what you&#8217;re doing when you <br /> draw great-circles from A to B; you&#8217;re using A as your &quot;north pole&quot;, and <br /> putting B on a meridian. <br /> &#8212; <br /> Roy Smith &lt;r&#8230;@nyu.edu&gt; <br /> Hippocrates Project, Department of Microbiology, Coles 202 <br /> NYU School of Medicine, 550 First Avenue, New York, NY 10016 <br /> &quot;This never happened to Bart Simpson.&quot; </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6941</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:48 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6941</guid>
		<description>
  &lt;p&gt;&gt; Yes it would. &#160;Although visible light won&#039;t follow the curvature of the &lt;br /&gt; &gt; Earth&#039;s surface, if you try some other sort of electromagnetic radiation of &lt;br /&gt; &gt; a slightly lower frequency (say, 1 MHz), it&#039;ll follow the surface just fine, &lt;br /&gt; &gt; and yes indeed, it will trace out a great circle. &lt;br /&gt; &lt;br /&gt;VOR signals do not need to follow the curve of the earth. &#160;They are line &lt;br /&gt; of &lt;br /&gt; sight. &#160;But they still travel in straight lines, and a give VOR radial &lt;br /&gt; will &lt;br /&gt; be a plane that follows the area over the great circle. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;-Ron &lt;br /&gt;
  
  &lt;/p&gt;</description>
		<content:encoded><![CDATA[<p>&gt; Yes it would. &nbsp;Although visible light won&#8217;t follow the curvature of the <br /> &gt; Earth&#8217;s surface, if you try some other sort of electromagnetic radiation of <br /> &gt; a slightly lower frequency (say, 1 MHz), it&#8217;ll follow the surface just fine, <br /> &gt; and yes indeed, it will trace out a great circle. </p>
<p>VOR signals do not need to follow the curve of the earth. &nbsp;They are line <br /> of <br /> sight. &nbsp;But they still travel in straight lines, and a give VOR radial <br /> will <br /> be a plane that follows the area over the great circle.  </p>
<p>-Ron </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6939</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:47 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6939</guid>
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  &lt;p&gt;Mark Mallory (mmall...@netcom.com) wrote: &lt;br /&gt; &lt;br /&gt;: The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a &lt;br /&gt; : radial will be constant *only* if that radial happens to lie along an &lt;br /&gt; : isogonic line. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;Oh, my... here I am responding to my own post! &#160;While staring at a Canadian &lt;br /&gt; WAC chart this afternoon and observing the isogonic lines (running nearly &lt;br /&gt; E-W), I suddenly realized that my above statement is not correct! &#160;An &lt;br /&gt; isogonic line is a line of constant difference between *true* and &lt;br /&gt; *magnetic* direction. &#160;If the radial and isogonic line I referred to above &lt;br /&gt; lie in any direction other than (true) N-S, the true course will be &lt;br /&gt; changing along the radial and the magnetic course will be changing as &lt;br /&gt; well - maintaining a constant offset with the true course, *not* a &lt;br /&gt; constant magnetic course. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;So although I still stand by the first paragraph of my response, I hereby &lt;br /&gt; retract the second paragraph, above. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;(I feel so much better now...) &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>Mark Mallory (mmall&#8230;@netcom.com) wrote: </p>
<p>: The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a <br /> : radial will be constant *only* if that radial happens to lie along an <br /> : isogonic line.  </p>
<p>Oh, my&#8230; here I am responding to my own post! &nbsp;While staring at a Canadian <br /> WAC chart this afternoon and observing the isogonic lines (running nearly <br /> E-W), I suddenly realized that my above statement is not correct! &nbsp;An <br /> isogonic line is a line of constant difference between *true* and <br /> *magnetic* direction. &nbsp;If the radial and isogonic line I referred to above <br /> lie in any direction other than (true) N-S, the true course will be <br /> changing along the radial and the magnetic course will be changing as <br /> well &#8211; maintaining a constant offset with the true course, *not* a <br /> constant magnetic course.  </p>
<p>So although I still stand by the first paragraph of my response, I hereby <br /> retract the second paragraph, above.  </p>
<p>(I feel so much better now&#8230;) </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6937</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6937</guid>
		<description>
  &lt;p&gt;Mark Mallory wrote: &lt;br /&gt; &gt; The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a &lt;br /&gt; &gt; radial will be constant *only* if that radial happens to lie along an &lt;br /&gt; &gt; isogonic line. &lt;br /&gt; &lt;br /&gt;Isogonic lines have nothing to do with it. &lt;br /&gt;
  
  &lt;/p&gt;</description>
		<content:encoded><![CDATA[<p>Mark Mallory wrote: <br /> &gt; The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a <br /> &gt; radial will be constant *only* if that radial happens to lie along an <br /> &gt; isogonic line. </p>
<p>Isogonic lines have nothing to do with it. </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6938</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6938</guid>
		<description>
  &lt;p&gt;In article 3...@zoom2.telepath.com, i...@intellisys.net (brian whatcott) writes: &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&gt; In article &lt;31E707FE....@vgernet.net&gt;, robe...@vgernet.net says... &lt;br /&gt; &gt; &gt;Sorry guys, a VOR radial isn&#039;t a GCc. It is a magnetic course. Need a &lt;br /&gt; &gt; &gt;magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), &lt;br /&gt; &gt; &gt;is a constant curve (i.e., constantly changing mag course), albeit, on &lt;br /&gt; &gt; &gt;short legs it would be hard to tell the difference. &lt;br /&gt; &gt; Yep, this is what the PPLs are taught, no doubt. &lt;br /&gt; &gt; &#160; Now here&#039;s the scoop. &lt;br /&gt; &gt; Electromagnetic waves travel in straight lines &lt;br /&gt; &gt; &#160;( ignoring the numerous refractive and releativistic cases). &lt;br /&gt; &gt; Imagine a thin, thin &#160;fan beam of light shining from a transmitter site, &lt;br /&gt; &gt; &#160;with its thin dimension horizontal and its wide dimension vertical and &lt;br /&gt; &gt; its other long dimension starting out along a magnetic radial. &lt;br /&gt; &gt; It travels in a straight line. &lt;br /&gt; &gt; If you follow this fan of light at constant height above the Earth&#039;s &lt;br /&gt; &gt; &#160;surface, you follow a great-circle. &lt;br /&gt; &lt;br /&gt;&#160; Maybe someone already responded to this, but if not I&#039;ll raise the &lt;br /&gt; &#160; question... Isn&#039;t it required for a great circle route to be the &lt;br /&gt; &#160; intersection of the surface of the earth with a plane passing &lt;br /&gt; &#160; through the two points of interest (A and B) and the center of the &lt;br /&gt; &#160; earth? &#160; &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&#160; If you shoot a beam of light directly from A to B, even if it were &lt;br /&gt; &#160; to follow the curved surface of the earth, I don&#039;t believe this would &lt;br /&gt; &#160; always result in a great circle route. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&#160; If I&#039;m wrong, I have no doubt I&#039;ll be shown the error of my ways! &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&#160; ---Tom T. &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>In article <a href="mailto:3...@zoom2.telepath.com">3&#8230;@zoom2.telepath.com</a>, <a href="mailto:i...@intellisys.net">i&#8230;@intellisys.net</a> (brian whatcott) writes:  </p>
<p>&gt; In article &lt;31E707FE&#8230;.@vgernet.net&gt;, <a href="mailto:robe...@vgernet.net">robe&#8230;@vgernet.net</a> says&#8230; <br /> &gt; &gt;Sorry guys, a VOR radial isn&#8217;t a GCc. It is a magnetic course. Need a <br /> &gt; &gt;magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), <br /> &gt; &gt;is a constant curve (i.e., constantly changing mag course), albeit, on <br /> &gt; &gt;short legs it would be hard to tell the difference. <br /> &gt; Yep, this is what the PPLs are taught, no doubt. <br /> &gt; &nbsp; Now here&#8217;s the scoop. <br /> &gt; Electromagnetic waves travel in straight lines <br /> &gt; &nbsp;( ignoring the numerous refractive and releativistic cases). <br /> &gt; Imagine a thin, thin &nbsp;fan beam of light shining from a transmitter site, <br /> &gt; &nbsp;with its thin dimension horizontal and its wide dimension vertical and <br /> &gt; its other long dimension starting out along a magnetic radial. <br /> &gt; It travels in a straight line. <br /> &gt; If you follow this fan of light at constant height above the Earth&#8217;s <br /> &gt; &nbsp;surface, you follow a great-circle. </p>
<p>&nbsp; Maybe someone already responded to this, but if not I&#8217;ll raise the <br /> &nbsp; question&#8230; Isn&#8217;t it required for a great circle route to be the <br /> &nbsp; intersection of the surface of the earth with a plane passing <br /> &nbsp; through the two points of interest (A and B) and the center of the <br /> &nbsp; earth? &nbsp;  </p>
<p>&nbsp; If you shoot a beam of light directly from A to B, even if it were <br /> &nbsp; to follow the curved surface of the earth, I don&#8217;t believe this would <br /> &nbsp; always result in a great circle route.  </p>
<p>&nbsp; If I&#8217;m wrong, I have no doubt I&#8217;ll be shown the error of my ways!  </p>
<p>&nbsp; &#8212;Tom T. </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6935</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6935</guid>
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  &lt;p&gt;Robert Allardyce (robe...@vgernet.net) wrote: &lt;br /&gt; &lt;br /&gt;: Sorry guys, a VOR radial isn&#039;t a GCc. It is a magnetic course. Need a &lt;br /&gt; : magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), &lt;br /&gt; : is a constant curve (i.e., constantly changing mag course), albeit, on &lt;br /&gt; : short legs it would be hard to tell the difference. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;WRONG. &#160;A VOR radial is a great circle defined by a magnetic bearing from &lt;br /&gt; the station. &#160;This is because radio signals tend to travel the path of &lt;br /&gt; *least distance* between transmitter and receiver - and a great circle is &lt;br /&gt; just such a least distance path along the earth&#039;s surface. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a &lt;br /&gt; radial will be constant *only* if that radial happens to lie along an &lt;br /&gt; isogonic line. &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>Robert Allardyce (robe&#8230;@vgernet.net) wrote: </p>
<p>: Sorry guys, a VOR radial isn&#8217;t a GCc. It is a magnetic course. Need a <br /> : magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), <br /> : is a constant curve (i.e., constantly changing mag course), albeit, on <br /> : short legs it would be hard to tell the difference.  </p>
<p>WRONG. &nbsp;A VOR radial is a great circle defined by a magnetic bearing from <br /> the station. &nbsp;This is because radio signals tend to travel the path of <br /> *least distance* between transmitter and receiver &#8211; and a great circle is <br /> just such a least distance path along the earth&#8217;s surface.  </p>
<p>The &quot;magnetic heading&quot; (actually magnetic track) required to stay on a <br /> radial will be constant *only* if that radial happens to lie along an <br /> isogonic line. </p>
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		<title>By: admin</title>
		<link>http://www.foraviators.info/great-circle-question/comment-page-1#comment-6936</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 30 Mar 2010 08:09:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.foraviators.info/great-circle-question#comment-6936</guid>
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  &lt;p&gt;In article &lt;31E707FE....@vgernet.net&gt;, robe...@vgernet.net says... &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&lt;/p&gt;&lt;p&gt;&gt;Sorry guys, a VOR radial isn&#039;t a GCc. It is a magnetic course. Need a &lt;br /&gt; &gt;magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), &lt;br /&gt; &gt;is a constant curve (i.e., constantly changing mag course), albeit, on &lt;br /&gt; &gt;short legs it would be hard to tell the difference. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&gt;R.A. &lt;br /&gt; &lt;br /&gt;Yep, this is what the PPLs are taught, no doubt. &lt;br /&gt; &#160; Now here&#039;s the scoop. &lt;br /&gt; Electromagnetic waves travel in straight lines &lt;br /&gt; &#160;( ignoring the numerous refractive and releativistic cases). &lt;br /&gt; &lt;/p&gt;&lt;p&gt;Imagine a thin, thin &#160;fan beam of light shining from a transmitter site, &lt;br /&gt; &#160;with its thin dimension horizontal and its wide dimension vertical and &lt;br /&gt; its other long dimension starting out along a magnetic radial. &lt;br /&gt; It travels in a straight line. &lt;br /&gt; If you follow this fan of light at constant height above the Earth&#039;s &lt;br /&gt; &#160;surface, you follow a great-circle. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;&#160;Yep, there it is. &lt;br /&gt; Now; live with it. &lt;br /&gt; &lt;/p&gt;&lt;p&gt;brian &lt;br /&gt;
  
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		<content:encoded><![CDATA[<p>In article &lt;31E707FE&#8230;.@vgernet.net&gt;, <a href="mailto:robe...@vgernet.net">robe&#8230;@vgernet.net</a> says&#8230;  </p>
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<p>&gt;Sorry guys, a VOR radial isn&#8217;t a GCc. It is a magnetic course. Need a <br /> &gt;magnetic heading to stay on it. A GCc, by nature(i.e., spherical trig), <br /> &gt;is a constant curve (i.e., constantly changing mag course), albeit, on <br /> &gt;short legs it would be hard to tell the difference.  </p>
<p>&gt;R.A. </p>
<p>Yep, this is what the PPLs are taught, no doubt. <br /> &nbsp; Now here&#8217;s the scoop. <br /> Electromagnetic waves travel in straight lines <br /> &nbsp;( ignoring the numerous refractive and releativistic cases).  </p>
<p>Imagine a thin, thin &nbsp;fan beam of light shining from a transmitter site, <br /> &nbsp;with its thin dimension horizontal and its wide dimension vertical and <br /> its other long dimension starting out along a magnetic radial. <br /> It travels in a straight line. <br /> If you follow this fan of light at constant height above the Earth&#8217;s <br /> &nbsp;surface, you follow a great-circle.  </p>
<p>&nbsp;Yep, there it is. <br /> Now; live with it.  </p>
<p>brian </p>
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